1z1-106 Valid Exam Dumps | Exam 1z1-106 Simulator Free
1z1-106 Valid Exam Dumps | Exam 1z1-106 Simulator Free
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Oracle 1Z0-106 certification exam is a multiple-choice exam that consists of 60 questions that are to be answered within 120 minutes. 1z1-106 Exam is designed to test the candidate's proficiency in various areas, including advanced system administration tasks, networking, storage, services, and security on Oracle Linux 8. 1z1-106 exam is conducted online, and candidates will receive their results immediately after the exam.
Earning the Oracle 1Z0-106 Certification provides IT professionals with several benefits, including increased job opportunities, higher salaries, and recognition among peers. By demonstrating the ability to work with Oracle Linux 8 in an enterprise environment, professionals can enhance their career prospects and take on more challenging roles in the IT industry.
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Oracle Linux 8 Advanced System Administration Sample Questions (Q31-Q36):
NEW QUESTION # 31
Which two statements are true about the Linux Auditing System?
- A. Auditing system call rules can affect system performance depending on the amount of information that is logged.
- B. Auditing includes security policies, each of which includes security rules, or checks, which are checked when you run a security scan.
- C. Auditing rules can log administrator attempts to access user home directories.
- D. Auditing modes include permissive, enforcing, and disabled.
- E. Auditing can scan for Common Vulnerabilities and Exposures (CVE) and automatically apply needed patches to a system.
Answer: A,C
NEW QUESTION # 32
Examine these commands executed by root:
# mkdir -p /jail /jail/bin /jail/lib64
# cp $(which bash) /jail/bin/
# ldd $(which bash)
linux-vdso.so.1 (0x00007ffd574f5000)
libtinfo.so.6 => /lib64/libtinfo.so.6 (0x00007fb458c2c000)
libdl.so.2 => /lib64/libdl.so.2 (0x00007fb458a28000)
libc.so.6 => /lib64/libc.so.6 (0x00007fb458666000)
/lib64/ld-linux-x86-64.so.2 (0x00007fb459177000)
# cp /lib64/libtinfo.so.6 /jail/lib64/
# cp /lib64/libdl.so.2 /jail/lib64/
# cp /lib64/libc.so.6 /jail/lib64/
# cp /lib64/ld-linux-x86-64.so.2 /jail/lib64/
# chroot /jail
What is the output from the cd, pwd, and ls commands?
- A. bash-4.4# cd
bash: cd: /root: No such file or directory
bash-4.4# pwd
/root
bash-4.4# ls
bash: ls: command not found - B. bash-4.4# cd
bash: cd: /root: Unable to access chrooted file or directory /root
bash-4.4# pwd
/
bash-4.4# ls
bin lib64 - C. bash-4.4# cd
bash: cd: command not found
bash-4.4# pwd
bash: pwd: command not found
bash-4.4# ls
bash: ls: command not found - D. bash-4.4# cd
bash: cd: /root: No such file or directory
bash-4.4# pwd
/
bash-4.4# ls
bin lib64
Answer: D
Explanation:
Explanation of Answer A:When thechrootcommand is executed with/jail, the environment is changed to use
/jailas its new root directory. Inside this environment, only the directories and files copied into/jailare accessible. Since/jaildoes not contain a/rootdirectory, the commandcd(which defaults to changing to the user's home directory) will fail, displayingNo such file or directory. Thepwdcommand shows the root of the chroot environment (/), andlsdisplays the contents of/jail, which includesbinandlib64.
NEW QUESTION # 33
Examine the contents of the /etc/exports file on an NFS server:
/status *(rw,async)
/usr/shared/tools *(all-squash,anonuid=501,anongid=501,ro)
/projects/big *(ro) pteam(rw)
The NFS server exports /usr/shared/tools to NFS clients. Which statement is true?
- A. All clients can mount /usr/shared/tools read-only and NFS explicitly maps all requests to the UID and GID of the unprivileged local 501 user.
- B. All clients can mount /usr/shared/tools read-only and NFS explicitly maps all requests to the UID and GID of the privileged local 501 user.
- C. All clients can mount /usr/shared/tools read-only and all-squash overrides explicit mapping of the UID and GID defined by anonuid and anongid.
- D. All clients except those with a local 501 user can mount /usr/shared/tools read-only.
- E. All clients can mount /usr/shared/tools read-only and NFS ignores the directives defined by the anonuid and anongid options.
Answer: A
Explanation:
* Option C (Correct):Theall-squashoption in the/etc/exportsfile maps all user and group requests from remote systems to the anonymous user (nfsnobody) on the NFS server. However, because theanonuidandanongidoptions are specified with501, all incoming requests are explicitly mapped to the UID and GID of the unprivileged local user with UID 501 and GID 501. Thero(read-only) option allows all clients to mount/usr/shared/toolsas read-only.
* Option A (Incorrect):This is incorrect because all clients can mount the directory, but all users' requests are squashed to UID 501. There is no exception for local 501 users.
* Option B (Incorrect):The answer is incorrect because it incorrectly states "privileged local 501 user." The UID 501 is typically an unprivileged user.
* Option D (Incorrect):Theall-squashoption does not override the UID and GID explicitly defined byanonuidandanongid. Instead, it maps all remote requests to these values.
* Option E (Incorrect):Theanonuidandanongiddirectives are not ignored; they are explicitly used to map all requests to the specified UID and GID.
Oracle Linux Reference:For more information on NFS exports and options, refer to:
* OracleLinux 8: Managing NFS and NIS
* man exportsfor details on export options.
NEW QUESTION # 34
Which two statements are true about control groups (cgroups) in Oracle Linux 8?
- A. A cgroup is a collection of processes bound to a set of limits or parameters defined in the cgroups filesystem.
- B. Cgroups allow processes to be organized into hierarchical groups whose resource usage cannot be limited and monitored.
- C. Different controllers from cgroups version 1 and cgroups version 2 cannot be used at the same time.
- D. The cgroups filesystem allows limits to be overwritten in the lower levels of the hierarchy.
- E. Oracle Linux 8 implements cgroups v2 by default.
Answer: A,E
NEW QUESTION # 35
Which statement is true about slice units?
- A. A slice unit is a concept for hierarchically managing resources in a group of processes.
- B. Processes in a slice unit are named at the same level as scopes and services.
- C. A slice unit accepts multiple names by the creation of additional symlinks to the unit file.
- D. The system.slice contains all system services and user sessions.
Answer: A
Explanation:
* Option A (Correct):A slice unit in systemd is a grouping mechanism used for hierarchical management of resources (such as CPU, memory, and I/O) among a group of processes.
* Options B, C, D (Incorrect):These options do not correctly describe the role or characteristics of slice units in Oracle Linux 8.
Oracle Linux Reference:Refer to:
* OracleLinux 8: Managing Services with systemd
NEW QUESTION # 36
......
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